The resistance of $1 N$ solution of acetic acid is $250 o h m$ , when measured in a cell having a cell constant of $1.15 {c m}^{- 1}$ . The equivalent conductance (in ${o h m}^{- 1} {c m}^{2} {e q u i v}^{- 1}$ ) of $1 N$ acetic acid is:

2.3

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4.6

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9.2

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18.4

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Solution

The correct option is B $4.6$
Equivalent conductivity $(κ) = \frac{c e l l c o n s t a n t}{r e s i s t a n c e} = \frac{1.15}{250} S {c m}^{- 1}$
$∴ Λ_{e q} = \frac{1.15 \times 1000}{250 \times 1}$

$Λ_{e q} = 4.6 {o h m}^{- 1} {c m}^{2} {e q u i v}^{- 1}$

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The resistance of 1N solution of acetic acid is 250ohm, when measured in a cell having a cell constant of 1.15cm−1. The equivalent conductance (in ohm−1cm2equiv−1) of 1N acetic acid is:

The correct option is B 4.6Equivalent conductivity (κ)=cellconstantresistance=1.15250Scm−1∴Λeq=1.15×1000250×1Λeq=4.6ohm−1cm2equiv−1

The resistance of $1 N$ solution of acetic acid is $250 o h m$ , when measured in a cell having a cell constant of $1.15 {c m}^{- 1}$ . The equivalent conductance (in ${o h m}^{- 1} {c m}^{2} {e q u i v}^{- 1}$ ) of $1 N$ acetic acid is:

The correct option is B $4.6$
Equivalent conductivity $(κ) = \frac{c e l l c o n s t a n t}{r e s i s t a n c e} = \frac{1.15}{250} S {c m}^{- 1}$
$∴ Λ_{e q} = \frac{1.15 \times 1000}{250 \times 1}$

$Λ_{e q} = 4.6 {o h m}^{- 1} {c m}^{2} {e q u i v}^{- 1}$