The resistance of a 0.02N solution of an electrolyte MgCl2 was found to be 210ohm at 298K using a conductivity cell with a cell constant of 0.88cm−1. Calculate the equivalent conductivity of the solution.
A
500ohm−1cm2eq−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
209.5ohm−1cm2eq−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
625ohm−1cm2eq−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
125.5ohm−1cm2eq−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B209.5ohm−1cm2eq−1 Given: Cell constant, lA=0.88cm−1Resistance, R=210ohm
Specific conductance, κ=lA×1R
κ=0.88×1210=4.19×10−3ohm−1cm−1
Equivalent conductance is the conductivity of a solution containing 1 g-equivalent of the electrolyte.
Λeq=κV V is volume of solution containing 1g−equiv
Normality of solution→N Ng−equiv of solute present in →1L solution
1g−equiv of solute present in →1NL solution ∴ Λeq=κN(when volume in litres)