The resistance of a 0.5M solution of an electrolyte in a cell was found to be 50Ω. If the electrodes in the cell are 2.2cm apart and have an area of 4.4cm2 then the molar conductivity (in Sm2mol−1) of the solution is:
A
0.2
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B
0.02
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C
0.002
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D
None of these
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Solution
The correct option is B 0.02 Conductivity(k)=Conductance×cellconstant k=150×2.24.4=0.01Ω−1cm−1 molar conductivity, λm=k×1000C =0.01×10000.5=20Ω−1cm2mol−1 =0.02Ω−1m2mol−1