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Question

The resistance of a 0.5 M solution of an electrolyte in a cell was found to be 50 Ω. If the electrodes in the cell are 2.2 cm apart and have an area of 4.4 cm2 then the molar conductivity (in Sm2mol1) of the solution is:

A
0.2
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B
0.02
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C
0.002
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D
None of these
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Solution

The correct option is B 0.02
Conductivity(k)=Conductance×cell constant
k=150×2.24.4=0.01 Ω1cm1
molar conductivity, λm=k×1000C
=0.01×10000.5=20 Ω1cm2mol1
=0.02 Ω1m2mol1

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