The resistance of a 1 m long nichrome wire is 6 Ω. If we reduce the length of wire to 70 cm, what will be its new resistance?
4.2 Ω
Given: Resistance of 1 m(100 cm) long nichrome wire R1=6 Ω
Length of nichrome wire L1=100 cm
Reduced length L2=70 cm
Let the new resistance be R2.
Here, the value of ρ and area of cross-section A will not change.
Therefore, resistance is directly proportional to the length of the wire, so R1R2=L1L2.
On substituting the values, we get 6R2=10070
⇒ R2=4.2 Ω