Question

The resistance of a conductivity cell containing $0.0001MKCl$ solution at $298K$ is $1500$ $\Omega$
. What is the cell constant ( in $c{m}^{-1}$) if conductivity of $0.0001MKCl$ solution at $298K$ is $0.146\times {10}^{-3}{\text{S cm}}^{-1}$.

Answer 1

$\text{Cell Constant}=\frac{\text{Conductivity}}{\text{Conductance}}$
$=\text{Conductivity}\times \text{Resistance}$
$=0.146\times {10}^{-3}\times 1500=0.219{\text{cm}}^{-1}$