Question

the resistance of a conductor is reduced to 1/2 its initial value . in doing so the heating effects in the conductor will become:
1. 1/2 2. 1/4 3. 4 times 4. double

Answer 1

$$\begin{gathered} \mathrm{H}={\mathrm{I}}^2\mathrm{Rt} \\ \mathrm{H}\mathrm{\alpha }\mathrm{R} \\ \mathrm{R}=\frac{1}{2} \\ \mathrm{So},\mathrm{H}=\frac{1}{2} \\ \mathrm{Hence},\mathrm{the}\mathrm{heating}\mathrm{effects}\mathrm{in}\mathrm{the}\mathrm{conductor}\mathrm{will}\mathrm{becom}\mathrm{half}. \end{gathered}$$