The resistance of a conductor is reduced to half its initial value keeping the current constant. In doing so the heating effects in the conductor will become

half

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double

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one-fourth

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four times

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Solution

The correct option is A half
Heat produced= $H = i^{2} R t$

Keeping $i$ constant $H \propto R$

Hence, on reducing resistance to half, Heat produced also becomes $h a l f$ of initial value.

Answer-(A)

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