The resistance of a wire at 20∘C is 20Ω and at 500∘C is 60Ω. At which temperature resistance will be 25Ω
A
50∘C
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B
60∘C
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C
70∘C
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D
80∘C
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Solution
The correct option is D80∘C By using R1R2=(1+αt1)(1+αt2)⇒2060=1+20α1+500α⇒α=1220 Again by using the same formula for 20Ω and 25Ω⇒2025=(1+1220×20)(1+1220×t)⇒t=80∘C