The resistance of a wire is quadrupled, when the length of the wire is doubled and diameter of wire is constant.
The resistance of a wire, of length 'l', is RΩ. The wire is stretched to double its length keeping the volume constant. The resistance of the wire will become?
A copper wire has diameter 0.5 mm and resistivity of 1.6 × 10−8 Ω m. What will be the length of this wire to make its resistance 10 Ω? How much does the resistance change if the diameter is doubled?