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Resistivity

The resistanc...

Question

The resistance of an ammeter of $1.0 A$ range is $0.018 Ω$ .How will you convert it an ammeter measuring up to $10 A$ ? What is thee resistance of the new ammeter?

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Solution

V $=$ IR
$I \propto \frac{1}{R}$
$∴ \frac{I_{1}}{I_{2}} = \frac{R_{2}}{R_{1}}$
$I_{1} = 1 A$
$R_{1} = 0.018 A$
$I_{2} = 10 A$
$R_{2} = ?$
$R_{2} = \frac{I_{1} R_{1}}{I_{2}} = \frac{1 \times 0.018}{10} = 0.0018$ .

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