The resistance of each arm of a wheatstone bridge is 10 ohm. A resistance of 10 ohm is connected in series with the galvanometer. The equivalent resistance of the bridge across the battery is

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$I n a b a l a n c e d w h e a t s t o n e b r i d g e w h e n t h e p o t e n t i a l d r o p a c r o s s t h e g a l v a n o m e t e r i s z e r o . s o e v e n w h e n a r e s i s t o r i s c o n n e c t e d i n s e r i e s w i t h t h e g a l v a n o m e t e r t h e r e i s n o c u r r e n t i n i t . s o u p p e r a r m r e s i s \tan c e s a r e c o n n e c t e d i n s e r i e s s o R_{1} = 10 + 10 = 20 Ω a n d r e s i s \tan c e o f t h e l o w e r a r m r e s i s \tan c e s i s R_{2} = 10 + 10 = 20 Ω s o t h e t w o r e s i s \tan c e s a r e c o n n e c t e d i n p a r a l l e l \frac{1}{R_{e q v}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} \frac{1}{R_{e q v}} = \frac{1}{20} + \frac{1}{20} \frac{1}{R_{e q v}} = \frac{2}{20} = \frac{1}{10} R_{e q v} = 10 Ω R e g a r d s$

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In a Wheatstone bridge the four arms have each a resistance of 50 ohm. The galvanometer current is :

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