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Question

The resistance of N/10 solution is found to be 2.5×103ohm. The equivalent conductance of the solution is (cell constant =1.25 cm1).

A
2.5 ohm1cm2equiv1
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B
5 ohm1cm2equiv1
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C
2.5 ohm1cm2equiv1
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D
5 ohm1cm2equiv1
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Solution

The correct option is A 5 ohm1cm2equiv1
Given Data : 1) Resistance = R = 2.5×103
2) Cell constant = k = la= 1.15cm2
3) Normality =N= 0.1N
To Find : Equivalent conductance = Λeq

The relation between K ,R and k is,
K = 1R×la
where K is specific conductance.
Substituting the given values we get,

K = 12.5×103 × 1.15cm1

= 1.152.5×103 ohm1cm1

The relation between Λeq and K is,

Λeq = K×1000N

Substituting the value of M and K we get,

Λeq=1.152.5×103×0.1×1000

= 4.6ohm1cm2equi1 [Note:Normality= no. of equiv./cm3]

Here appproximation is taken,

5 ohm1cm2equi1

Hence the correct option is 'B'.


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