The correct option is
A 5 ohm−1cm2equiv−1Given Data : 1) Resistance =
R =
2.5×103 2) Cell constant = k = la= 1.15cm2
3) Normality =N= 0.1N
To Find : Equivalent conductance = Λeq
The relation between K ,R and k is,
K = 1R×la
where K is specific conductance.
∴ Substituting the given values we get,
K = 12.5×103 × 1.15cm−1
= 1.152.5×103 ohm−1cm−1
The relation between Λeq and K is,
Λeq = K×1000N
Substituting the value of M and K we get,
Λeq=1.152.5×103×0.1×1000
= 4.6ohm−1cm2equi−1 [Note:Normality= no. of equiv./cm3]
Here appproximation is taken,
≈ 5 ohm−1cm2equi−1
Hence the correct option is 'B'.