Question

The resistance of $N/2$ solution of an electrolyte in a cell was found to be $45$ ohm. The equivalent conductivity of a solution, if the electrodes in the cell are $2.2$ cm apart and have an area of $3.8c{m}^2$ will be:

• A. $52.72Sc{m}^{2}e{q}^{-1}$
• B. $22.57Sc{m}^{2}e{q}^{-1}$
• C. $27.52Sc{m}^{2}e{q}^{-1}$
• D. $25.72Sc{m}^{2}e{q}^{-1}$

Answer 1

The correct option is D $25.72Sc{m}^{2}e{q}^{-1}$

Cell constant = $\frac{l}{a}=\frac{2.2}{3.8}=0.579c{m}^{-1}$

Specific conductance = cell constant $\times$ conductance

Specific conductance = $\frac{0.579}{45}$

Equivalent conductance= $\frac{0.579}{45}\times \frac{1000}{0.5}$

Equivalent conductance = $25.73Sc{m}^{2}e{q}^{-1}$

Hence, option D is correct.