wiz-icon
MyQuestionIcon
MyQuestionIcon
12
You visited us 12 times! Enjoying our articles? Unlock Full Access!
Question

The resistance of Resistor A is 4 times greater than the resistance of Resistor B, if resistance A and B are connected in series then compare the following
1. Currents through these resistors (IA and IB, respectively)
2. The voltage drops across them (VA and VB, respectively)

A
IA=IB and VA=VB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
IA=IB and VA=4VB
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
IA=IB and VB=4VA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
IA=4IB and VA=4VB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
IB=4IA and VB=4VA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A IA=IB and VA=4VB
Here, RA=4RB
Since the resistances A and B are connected in series so the same current will pass through them. Thus, IA=IB
By Ohm's law, VA=IARA=4IBRB=4VB

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cell and Cell Combinations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon