The resistance of the wire made of silver at 27oC temperature is equal to 2-1 -While at 100oC it is 2-7 -Calculate the temperature coefficient of the resistivity of the silver-Take the reference temperature is equal to 20oC

By formula , R_2=R_1[1+α(t_2 t_1)] R_2 R_1=R_1α(t_2 t_1) 2.7 2.1=2.1α(100 27.5) α=0.6/(2.1×72.5) 3.941×10^ 3 ^0C^1 ...

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Standard X

Physics

Ohm's Law

The resistanc...

Question

The resistance of the wire made of silver at $27^{o} C$ temperature is equal to $2.1 Ω$ .While at $100^{o} C$ it is $2.7 Ω$ .Calculate the temperature coefficient of the resistivity of the silver.Take the reference temperature is equal to $20^{o} C$

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Solution

By formula ,
$R_{2} = R_{1} [1 + α (t_{2} - t_{1})]$
$R_{2} - R_{1} = R_{1} α (t_{2} - t_{1})$
$2.7 - 2.1 = 2.1 α (100 - 27.5)$
$α = 0.6 / (2.1 \times 72.5)$
$3.941 \times 10^{-} 3^{0} C^{1}$

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The resistance of the wire made of silver at 27oC temperature is equal to 2.1Ω.While at 100oC it is 2.7Ω.Calculate the temperature coefficient of the resistivity of the silver.Take the reference temperature is equal to 20oC

By formula ,R2=R1[1+α(t2−t1)]R2−R1=R1α(t2−t1)2.7−2.1=2.1α(100−27.5)α=0.6/(2.1×72.5)3.941×10−30C1

The resistance of the wire made of silver at $27^{o} C$ temperature is equal to $2.1 Ω$ .While at $100^{o} C$ it is $2.7 Ω$ .Calculate the temperature coefficient of the resistivity of the silver.Take the reference temperature is equal to $20^{o} C$

By formula ,
$R_{2} = R_{1} [1 + α (t_{2} - t_{1})]$
$R_{2} - R_{1} = R_{1} α (t_{2} - t_{1})$
$2.7 - 2.1 = 2.1 α (100 - 27.5)$
$α = 0.6 / (2.1 \times 72.5)$
$3.941 \times 10^{-} 3^{0} C^{1}$