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Question

The resistance of wire is 20 ohm. The wire is stretched to three times of its length. Then the resistance will be :-

A
6.67Ω
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B
60Ω
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C
120Ω
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D
180Ω
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Solution

The correct option is D 180Ω
Resistance, R=ρlA
When length l increases three times, the cross section A will decease three times of previous. So length becomes 3l and cross section becomes A/3.
Now resistance becomes ,R=ρ3lπA/3=9R=9×20=180Ω

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