The resistance of wire is 20 ohm. The wire is stretched to three times of its length. Then the resistance will be :-
A
6.67Ω
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B
60Ω
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C
120Ω
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D
180Ω
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Solution
The correct option is D180Ω Resistance, R=ρlA When length l increases three times, the cross section A will decease three times of previous. So length becomes 3l and cross section becomes A/3. Now resistance becomes ,R′=ρ3lπA/3=9R=9×20=180Ω