Question

The resistance $R=\frac{V}{I}$, where $V=(50\pm 2)\text{V}$ and $I=(20\pm 0.2)\text{A}$. The percentage error in $R$ is ${}^{\prime }{x}^{\prime }\%$. The value of ${}^{\prime }{x}^{\prime }$ to the nearest integer is

Answer 1

Given, $R=\frac{V}{I}$

$\frac{\Delta R}{R}\times 100=\frac{\Delta V}{V}\times 100+\frac{\Delta I}{I}\times 100$

% error in $R=\frac{2}{50}\times 100+\frac{0.2}{20}\times 100$
$=4+1=5\%$

$\therefore$ $5$ is the required value.