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Question

# The resistivity of a conductor with a current density of 2.5Am−2 when an electric field 5×10−8Vm−1 is applied to it, is

A
1.0×108Ωm
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B
2.0×108Ωm
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C
0.5×108Ωm
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D
12.5×108Ωm
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Solution

## The correct option is B 2.0×10−8ΩmStep 1: Relation between Electric field(E), Resistivity and Current density(J)Suppose length of conductor =lWe know that, Potential difference, V=E.l& Current Density J=I/ASo, I=JAand R=ρlAFrom V=IR⇒E.l=JA×ρlA⇒E=J(ρ)∴ρ=EJStep 2: Putting the values in above equation⇒ρ=EJ=5×10−8Vm−12.5Am2 =2×10−8ΩmHence, Option B is correct

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