The resolving power of a microscope is

Inversely proportional to numerical aperture

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Directly proportional to wavelength

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Directly proportional to square of the wavelength

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Directly proportional to numerical aperture

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Independent of numerical aperture

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Solution

The correct option is E Directly proportional to numerical aperture
Resolving power of a microscope $= \frac{2 μ sin θ}{1.22 λ}$
i.e., resolving power of a microscope is directly proportional to numerical aperture.

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