The resolving power of a telescope depends upon the ...........

Length of the telescope

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Focal length of an objective

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Diameter of an objective

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Focal length of an eyepiece

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Diameter of an objective
R.P. of telescope $= \frac{1}{d θ} = \frac{a}{1.22 λ}$
Thus, it is clear that a telescope with a large diameter of the objective has higher resolving power. Thus, the resolving power of a telescope depends on the diameter of objective.

Suggest Corrections

Similar questions

Q. The diameter and the focal length of the objective of an astronomical telescope are

140

mm and

3.5

m respectively & focal length of the eyepiece is 25 mm. Find the magnifying power and resolving power of this telescope. Given : wavelength of yellow colour =

6000 A^{*}

A small telescope has an objective lens of focal length 144 cm and an eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?

Q. The eyepiece of an astronomical telescope has a focal length of 10 cm. The telescope is focussed for normal vision of distant objects when the tube length is 1.0. m. Find the focal length of the objective and the magnifying power of the telescope.

Q. The focal lengths of the eyepiece and the objective of an astronomical telescope are 2cm and 100cm respectively. The magnifying power of the telescope for normal adjustment and the length of the telescope are respectively:

Q. An astronomical refractive telescope has an objective of focal length 20 m and an eyepiece of focal length 2 cm. then

Join BYJU'S Learning Program

The resolving power of a telescope depends upon the ...........

The correct option is B Diameter of an objectiveR.P. of telescope =1dθ=a1.22λThus, it is clear that a telescope with a large diameter of the objective has higher resolving power. Thus, the resolving power of a telescope depends on the diameter of objective.

The correct option is B Diameter of an objective
R.P. of telescope $= \frac{1}{d θ} = \frac{a}{1.22 λ}$
Thus, it is clear that a telescope with a large diameter of the objective has higher resolving power. Thus, the resolving power of a telescope depends on the diameter of objective.