The resolving power of an electron micrsoscope operated at 16 $k V$ is $R$ . The resolving power of the electron microscope when operated at $4 k V$ is

\frac{R}{4}

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\frac{R}{2}

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4 R

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2 R

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Solution

The correct option is B $\frac{R}{2}$
Resolving power is proportional to inverse of wavelength
i.e. $R \propto$ $\frac{1}{λ}$
and $λ$ $\propto$ $\frac{1}{p}$
$R \propto$ $p$ = $\sqrt{2 m E}$
$R \propto$ $\sqrt{E}$
$\frac{R^{'}}{R} = \sqrt{\frac{4}{16}}$
$R^{'} = \frac{R}{2}$

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The resolving power of an electron micrsoscope operated at 16 kV is R. The resolving power of the electron microscope when operated at 4 kV is

The correct option is B R2Resolving power is proportional to inverse of wavelength i.e. R∝1λ and λ ∝ 1p R∝ p = √2mE R∝ √E R′R=√416 R′=R2

The resolving power of an electron micrsoscope operated at 16 $k V$ is $R$ . The resolving power of the electron microscope when operated at $4 k V$ is

The correct option is B $\frac{R}{2}$
Resolving power is proportional to inverse of wavelength
i.e. $R \propto$ $\frac{1}{λ}$
and $λ$ $\propto$ $\frac{1}{p}$
$R \propto$ $p$ = $\sqrt{2 m E}$
$R \propto$ $\sqrt{E}$
$\frac{R^{'}}{R} = \sqrt{\frac{4}{16}}$
$R^{'} = \frac{R}{2}$