Question

The resonating structures for $N_{2}O$ are given below :

Choose the correct decreasing order of stablity:

• A. $\left(i\right)>\left(ii\right)>\left(iii\right)$
• B. $\left(i\right)>\left(iii\right)>\left(ii\right)$
• C. $\left(ii\right)>\left(iii\right)>\left(i\right)$
• D. $\left(iii\right)>\left(ii\right)>\left(i\right)$

Answer 1

The correct option is A $\left(i\right)>\left(ii\right)>\left(iii\right)$

Negative charge on the more electronegative element and positive charge on more electropositive element is comparatively more stable.
Structure (i) is most stable because positive charge is on more electropositive atom i.e. nitrogen and negative charge on more electronegative atom i.e. oxygen.
In structure (iii), all the three atoms have formal charges on them and two like charges are closer to each other causing maximum repulsions.
Whereas in structure (ii) only two atoms have a charge on them. So (iii) is the least stable
Correct order is $\left(i\right)>\left(ii\right)>\left(iii\right)$