The respiratory quotient of the reaction given below is $2 (C_{51} H_{98} O_{6}) + 145 O_{2} \to 102 C O_{2} + 90 H_{2} O + e n e r g y$

0.703

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0.725

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0.96

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1.422

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Solution

The correct option is A 0.703
Respiratory quotient is defined as the ratio of the volume of CO $_{2}$ evolved to the volume of O $_{2}$ consumed in respiration.
So, from the given equation of respiration of Tripalmitin (C $_{5}$ $_{1}$ H $_{9}$ $_{8}$ O $_{6}$ )= Volume of CO $_{2}$ evoloved/Volume of O $_{2}$ comsumed,
= 102/145
= 0.703
So, the correct answer is '0.703'.

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2 (C_{51} H_{98} O_{6}) + 145 O_{2} \to 102 C O_{2} + 90 H_{2} O + e n e r g y

2 (C_{51} H_{98} O_{6}) + {145 O}_{2} \to {102 C O}_{2} + {98 H}_{2} O + E n e r g y

2 C_{51} H_{98} O_{6} + 146 O_{2} \to 102 C O_{2} + 98 H_{2} O

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