The resultant force of 5 N and 10 N can not be
12 N
8 N
4 N
5 N
Fmax=5+10=15 N and Fmin=10−5=5 N Range of resultant 5≤F≤15
Two forces are such that the sum of their magnitudes is 18 N and their resultant is perpendicular to the smaller force and magnitude of resultant is 12 N. Then the magnitudes of the forces are
A force of 5 N acts on a particle along a direction making an angle of 60∘ with vertical. Its vertical component be