The resultant of forces F-1-3i-4j-2k- F-2-2i-3j-k-F-3-2i-4j-5k- is-

The correct option is C 7i⃗+3j⃗ 4k⃗ F=F_1 +F_2 +F_3 #160; #160; =7i⃗+3j⃗ 4k⃗ ...

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Scalar and Vector Notation

The resultant...

Question

The resultant of forces ${\to F}_{1} = 3 \to i - 4 \to j + 2 \to k, {\to F}_{2} = 2 \to i + 3 \to j - \to k, {\to F}_{3} = 2 \to i + 4 \to j - 5 \to k$ is:

7 \to i - 11 \to j - 8 \to k

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7 \to i + 3 \to j - 6 \to k

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7 \to i + 3 \to j - 4 \to k

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7 \to i - 3 \to j + 4 \to k

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Solution

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Similar questions

2 \to i - \to j + \to k

\to i - 3 \to j - 5 \to k

- 3 \to i + 4 \to j + 4 \to k

\to r = (\to i + 2 \to j - 5 \to k) + t (2 \to i - 3 \to j + 4 \to k)

\to r \cdot (2 \to i + 4 \to j - \to k) = 3

A, B

C

2 \to i - \to j + \to k, \to i - 3 \to j - 5 \to k

3 \to i - 4 \to j - 4 \to k

{cos}^{2} A

3 \to i + 4 \to j + 2 \to k, 2 \to i - 2 \to j - \to k

7 \to i + \to j + \to k

2 \to i + 3 \to j + 4 \to k, 3 \to i + 2 \to j - 3 \to k

5 \to i + 5 \to j + \to k

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