Question

The resultant of the forces A and B is perpendicular to A Then the angle between them is :

Answer 1

$\left|A\right|=2\left|B\right|$

$Tan\beta =\frac{psin\theta }{q+pcos\theta }$

$P=\overrightarrow{A},Q=\overrightarrow{B}$

$\beta ={90}^0$

$\frac{1}{0}=\frac{Asin\theta }{B+Acos\theta }$

$B+Acos\theta =0$

$\frac{B}{A}=-cos\theta$

$cos\theta =-\frac{B}{2B}={120}^0$