The resultant of the three displacement vectors O-P-P-Q- and Q-R- is - cos 370-4-5

The correct option is B √(149) cm Resultant= 5cos 37 ^ 0 î +5sin 37 ^ 0 ĵ + 6î + 4ĵ =10î + 7ĵ Thus magnitude= √( 100+ 49 ) = √( 149 ) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Magnetic Flux and Faraday's Law

The resultant...

Question

The resultant of the three displacement vectors $\to O P, \to P Q$ and $\to Q R$ is :
$(cos 37^{0} = \frac{4}{5})$

15 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

17 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{149} c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{107} c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\to p = (2, - 4, 1), \to q = (3, - 1, 2), \to r = (5, 5, 4)

\to P Q

\to Q R

c m

\to O P =^i + 4^j - 3^k

\to O Q = 2^i - 2^j -^k

\to P Q

∣ ∣ \to P Q \times \to R S - \to Q R \times \to P S + \to R P \times \to Q S ∣ ∣

4

P Q R S, \to P Q = \to a, \to Q R = \to b, \to S P = \to a - \to b . M

Q R

X

S M

\to S X = \frac{4}{5} \to S M

\to P X

Join BYJU'S Learning Program