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Normal Reaction

The resultant...

Question

The resultant of two forces 1 and P is perpendicular to '1' and equal to 1. What is the value of 'P' and angle between the forces

\sqrt{2} N

135^{\circ}

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\sqrt{2} N

150^{\circ}

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2 N, 120^{\circ}

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2 N, 150^{\circ}

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Solution

The correct option is A $\sqrt{2} N$ , $135^{\circ}$
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