You visited us 1 times! Enjoying our articles? Unlock Full Access!

Net Force

The resultant...

Question

The resultant of two forces $P$ N and $3$ N is a force of $7$ N. If the direction of the $3$ N force were reversed, the resultant would be $\sqrt{19}$ N. The value of P is :

5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $5$ N
Here, $7^{2} = P^{2} + 3^{2} + 2 (P) (3) cos θ . . . . . (1)$
and $(\sqrt{19})^{2} = P^{2} + (- 3)^{2} + 2 (P) (- 3) cos θ . . . . . (2)$
$(1) + (2) \Rightarrow 49 + 19 = 2 P^{2} + 18$
or $P^{2} = 25 \Rightarrow P = 5 N$

Suggest Corrections

Similar questions

The sum of two forces acting at a point is 16 N. If the resultant force is 8 N and its direction is perpendicular to minimum force then the forces are

Q. Five forces

2 N, \sqrt{3} N, 5 N, \sqrt{3}

and

2 N

respectively and at a [article

P

as shown in the figure. The resultant force on the particle

P

Two forces, whose magnitude are at the ratio of 3:5 give a resultant of 35 N. If angle of inclination is 60^o, then the magnitude of each force is:

Q. The resultant force of

5 N

and

10 N

cannot be

Q. Two forces

3 N

and

2 N

at an angle

θ

such that resultant

R

. The first force is now increased to

6 N

and the resultant become

2 R

. The value of

θ

Join BYJU'S Learning Program

The resultant of two forces P N and 3 N is a force of 7 N. If the direction of the 3 N force were reversed, the resultant would be √19 N. The value of P is :

The correct option is A 5 NHere, 72=P2+32+2(P)(3)cosθ.....(1) and (√19)2=P2+(−3)2+2(P)(−3)cosθ.....(2) (1)+(2)⇒49+19=2P2+18or P2=25⇒P=5N

The resultant of two forces $P$ N and $3$ N is a force of $7$ N. If the direction of the $3$ N force were reversed, the resultant would be $\sqrt{19}$ N. The value of P is :

The correct option is A $5$ N
Here, $7^{2} = P^{2} + 3^{2} + 2 (P) (3) cos θ . . . . . (1)$
and $(\sqrt{19})^{2} = P^{2} + (- 3)^{2} + 2 (P) (- 3) cos θ . . . . . (2)$
$(1) + (2) \Rightarrow 49 + 19 = 2 P^{2} + 18$
or $P^{2} = 25 \Rightarrow P = 5 N$