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Question

The results of two plate load tests for a settlement of 25 mm are given below:

Plate diameter Load
0.3 m
0.6 m
30 kN
70 kN

What will be the size of square footing designed to carry a load of 900 kN as per Housel method ?

A
2.4 m
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B
2.7 m
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C
3 m
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D
2.9 m
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Solution

The correct option is D 2.9 m
A1=π4×0.32=0.07068 m2,Q1=30 kN,P1=π×0.3=0.9425 m

A2=π4×0.62=0.28274 m2,Q2=70 kN,P2=π×0.6=1.885 m

Q1=mA1+nP130=m×(0.07068)+n(0.9425) .........(1)

Q2=mA2+nP270=m×(0.28274)+n(1.885) .........(2)

Solving equation (1) and (2), we get

m = 70.73, n = 26.52

For Q = 900 kN

900=70.75B2+(4B)×26.52

B = 2.895 m = 2.9 m

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