The reusable booster rockets of the U.S. space shuttle uses a mixture of Aluminium and Ammonium perchlorate for fuel.
A possible equation for this reaction is:
$3 A l (s) + 3 N H_{4} C l O_{4} (s) \to A l_{2} O_{3} (s) + A l C l_{3} (s) + 3 N O_{(g)} + 6 H_{2} O_{(g)}$
What mass of $N H_{4} C l O_{4}$ should be used in the fuel mixture for every kilogram of $A l$ ?

3 k g

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3.388 k g

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4.351 k g

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4 k g

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Solution

The correct option is C $4.351 k g$
Given,
$3 A l (s) + 3 N H_{4} C l O_{4} (s) ⟶ A l_{2} O_{3} (s) + 3 N O (g) + 6 H_{2} O_{2} (g)$

$3$ moles of $A l$ consume $3$ moles of $N h_{4} C l O_{4}$
We know $3$ mole $A l = 3 \times 27 g / m o l$
$= 81 g m s$

Also $1 k g$ $A l = 1000 g$ $A l$

$1000 g$ $A l = \frac{1000 g}{27 g / m o l} = 37.037$ moles of $A l$

As in reaction $3$ moles $A l$ consume $3$ mole $N H_{4} C l O_{4}$

$\Rightarrow 37.037$ moles $A l$ consume $37.037$ moles $N H_{4} C l O_{4}$

$∴ 37.037$ mole $N H_{4} C l O_{4} = 37.037 m o l e \times 117.5 g / m o l$
$= 4351.84 g m s$

$= 4.351 K g$ $[∵$ Molar mass of $N H_{4} C l O_{4} = 117.5 g / m o l]$

Suggest Corrections

Similar questions

{N H}_{4} {C l O}_{4}

{N a C l O}_{4}

1.0 k g

N a C l + 4 H_{2} O ⟶ {N a C l O}_{4} + {4 H}_{2}

Aluminium is used in thermite welding:

(a) What is thermit?

(b) What is ignition mixture?

F e_{2} O_{3}

H_{f} (A l_{2} O_{3}) = 399

H_{f} (F e_{2} O_{3}) = 199

F e_{2} O_{3} = \frac{16}{3} g m / c c

{c m}^{3}

H_{f ({A l}_{2} O_{3})} = - 399 k c a l {m o l}^{- 1}; H_{f ({F e}_{2} O_{3})} = - 199 c a l {m o l}^{- 1}

{F e}_{2} O_{3} = 5.2 g / {c m}^{3}

A l = 2.7 g / {c m}^{3}

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