The reverberation time of a room is t seconds. Another room of double the dimensions with the walls of the same absorption coefficient will have a reverberation time :
A
t2
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B
2t
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C
t/2
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D
t3
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Solution
The correct option is B2t Given: V1V2=18A1A2=14 R.T.1=t R.T=0.161vA R.T.1R.T.2=0.161×v1A10.161×v2A2=v1A2v2A1=18×41=12 R.T2=2R.T1 =2×t =2t