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Question

# The reversible expansion of an ideal gas under adiatbatic and isothermal conditions is shown in the figure. Which of the following statement(s) is (are) correct?

A
T1=T2
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B
T3>T1
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C
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D
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Solution

## The correct options are B ΔUisothermal>ΔUadiabatic C wisothermal>wadiabatic D T1=T2As, (P1,V1,T1)→(P2,V2,T2) is an isothermal process, ΔT=0∴T1=T2Work done is equal to are under P−V graph. The area under P−V graph of the isothermal process is greater than that of the adiabatic process.∴Wisothermal>Wadiabatic→(i)Also, q=0 for adiabatic process.∴ΔUadiabatic=Wadiabatic (for adiabatic process) →(ii)& ΔUisothermal=qisothermal+Wisothermal→(iii)From (i), (ii) and (iii), it can be concluded thatΔUisothermal >ΔUadiabatic Hence, the correct options are A, C and D

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