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Question

The reversible expansion of an ideal gas under adiatbatic and isothermal conditions is shown in the figure. Which of the following statement(s) is (are) correct?
645671_44e7a8f9971442e597e80f55cad62447.PNG

A
T1=T2
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B
T3>T1
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C
wisothermal>wadiabatic
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D
ΔUisothermal>ΔUadiabatic
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Solution

The correct options are
B ΔUisothermal>ΔUadiabatic
C wisothermal>wadiabatic
D T1=T2

As, (P1,V1,T1)(P2,V2,T2) is an isothermal process, ΔT=0

T1=T2

Work done is equal to are under PV graph. The area under PV graph of the isothermal process is greater than that of the adiabatic process.

Wisothermal>Wadiabatic(i)

Also, q=0 for adiabatic process.

ΔUadiabatic=Wadiabatic (for adiabatic process) (ii)

& ΔUisothermal=qisothermal+Wisothermal(iii)

From (i), (ii) and (iii), it can be concluded that

ΔUisothermal >ΔUadiabatic

Hence, the correct options are A, C and D

1042620_645671_ans_166c7dc62a1342d89c03588ecc9e5c5e.png

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