The right order of ionization potential of Li, Be, B and C is :

C > B e > B > L i

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C > B > B e > L i

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C > B > L i > B e

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B > C > B e > L i

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Solution

The correct option is B $C > B e > B > L i$
The right order of ionization potential of $L i, B e, B$ and $C$ is $C > B e > B > L i$ . In a period the ionization potential increases from left to right due to an increase in the effective nuclear charge. The ionization potential of Be is higher than that of B. The electronic configurations of Be and B are $1 s^{2} 2 s^{2}$ and $1 s^{2} 2 s^{2} 2 p^{1}$ respectively. Less energy is required to remove p electron than s electron.
Option $A$ is correct.

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Arrange the following elements in the order of their increasing nonmetallic character
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