The correct option is D mod-3-down counter
Trick up/down = CP ⊕ Q, 1 for up and 0 for down.
CP = (clock pulse)
Q = (O/P)
0 = - ve edge; Q = 1
1 = + ve edge; ¯Q = 1
= 1 ⊕ 1 = 0 (down counter)
Counting sequence
1 1 1
1 1 0
1 0 1
1 0 0
0 1 1 (present state) so Mod 5