The rise of the water level in a capillary tube of radius 0.07cm when dipped vertically in a beaker containing water (assuming it to be perfectly wetting) will be. Given : Surface tension of water is 0.07Nm−1 and g=10ms−2
A
2cm
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B
4cm
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C
1.5cm
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D
3cm
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Solution
The correct option is A2cm Rise of a liquid in a capillary tube, h=2Tcosθrρg Here, r=0.07cm=0.07×10−2m For water, T=0.07Nm−1,ρ=103kg m−3 Angle of contact θ=0∘, for perfectly wetting characteristics. ⇒h=(2×0.07×1)(0.07×10−2)×(103)×(10) ∴h=2×10−2m=2cm