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Relating Translational KE and T

The rms speed...

Question

The rms speed of helium in $m s^{- 1}$ (atomic mass = $4.0 g m o l^{- 1}$ ) at 400 K is:

1580

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15.8

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28

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158

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Solution

Step 1:
$v_{r m s} = \sqrt{\frac{3 R T}{M}}$
$R = 8.314$
$T = 400 K$
Molar mass of helium is 0.004 Kg
Step 2:
$v_{r m s} = \sqrt{\frac{3 \times 8.314}{0.004}} = 1580 m s^{- 1}$

Hence, option (D) is correct.

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^{- 1}

^{- 1}

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(\frac{v_{r m s} (h e l i u m)}{v_{r m s} (a r g o n)})

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[\frac{V_{r m s} (h e l i u m)}{V_{r m s} (a r g o n)}]

If the rms speed of nitrogen molecules is $490 m s^{- 1}$ at 273K, find the rms speed of hydrogen molecules at the same temperature -

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