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Byju's Answer
Standard XII
Chemistry
Molecular Speeds - Vrms, Vavg, Vmps
The rms spe...
Question
The
r
m
s
speed of the molecules of a gas of density
4
k
g
m
−
3
and pressure
1.2
×
10
5
N
m
−
2
is........(in
m
/
s
e
c
)
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Solution
As we know,
u
r
m
s
=
√
3
R
T
/
M
=
√
3
P
V
/
M
=
√
3
P
/
d
u
r
m
s
=
√
3
P
d
=
√
3
×
1.2
×
10
5
4
=
3
×
10
2
m
s
−
1
=
300
m
/
s
e
c
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0
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Molecular Speeds - Vrms, Vavg, Vmps
Standard XII Chemistry
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