Question

The rms value of current $I_{rms}$ is
(where, $I_0$ is the value of peak current)

• A. $\frac{I_0}{2\pi }$
• B. $\frac{I_0}{\sqrt{2}}$
• C. $\frac{2I_0}{\pi }$
• D. $\sqrt{2}{I}_0$

Answer 1

The correct option is B $\frac{I_0}{\sqrt{2}}$

$I_{rms}=\sqrt{\frac{{\int }_0^T{I}_0^2{\sin }^2\omega tdt}{T}}=\frac{I_0}{\sqrt{2}}$ where $I_0$ is the peak current and $T$ is the time period.