The correct option is B 1√2A
Vs=Vmsinωt = 1 sint
Vm=1V and ω=1rad/sec
Impedance of the branch containing inductor and capacitor
Z=j(XL−XC)
=j(ωL−1ωC)
=j(1×1−11×1)=0
So, this branch is short-circuited and the whole currrent flow through it
i(t)=1sint1=1sint
Rms value of the current
=im√2
=1√2A