The $r m s$ velocity of hydrogen at $27^{o} C, R = 8.314 J m o l^{1} K^{1}$ is

1.934

m / s

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19.34

m / s

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193.4

m / s

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1934

m / s

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Solution

The correct option is D 1934 $m / s$
As we know,
$U_{r m s} = \sqrt{\frac{3 R T}{M_{w}}}$
$\Rightarrow \sqrt{\frac{3 \times 8.314 \times 300}{2 \times 10^{- 3}}}$
$U_{r m s}$ = 1934 $m / s$ .

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