The role of fluorspar $(C a F_{2})$ which is added during the electrolytic reduction of alumina dissolved in fused cryolite is:

to act as a catalyst

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to make the fused mixture very conducting

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to increase the temperature of the melt

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to decrease the rate of oxidation of carbon at the anode

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Solution

The correct option is B to make the fused mixture very conducting
The role of fluorspar is to reduce the melting point of mixture and improve the electrical conductivity of the melt as compared to molten $A l_{2} O_{3}$ . Hence, option B is the correct answer.

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Similar questions

Q. The major role of fluorspar

(C a F_{2})

which is added in small quantity in the electrolytic reduction of alumina dissolved in fused cryolite

(N a_{3} A l F_{6})

is :
I. to act as a catalyst
II. to make the fused mixture very conduction
III. to lower the temperature of melting
IV. to decrease the rate of oxidation of carbon at the anode

The role of fluorspar $(C a F_{2})$ which is added in small quantities in the electrolytic reduction of alumina dissolved in fused cryolite $(N a_{3} A l F_{6})$ is:

Q. The major role of fluorspar

(C a F_{2})

which is added in small quantities in the electrolytic reduction of alumina dissolved in fused cryolite

(N a_{3} A l F_{6})

is :

Q. The role of fluorspar, which is added in small quantities in the electrolysis reduction of alumina dissolved in fused cryolite, is:

Q. The major role of fluorspar which is added in small amount in the electrolytic reduction of

A l_{2} O_{3}

dissolved in fused cryolite is :

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The role of fluorspar (CaF2) which is added during the electrolytic reduction of alumina dissolved in fused cryolite is:

The correct option is B to make the fused mixture very conductingThe role of fluorspar is to reduce the melting point of mixture and improve the electrical conductivity of the melt as compared to molten Al2O3. Hence, option B is the correct answer.

The role of fluorspar $(C a F_{2})$ which is added during the electrolytic reduction of alumina dissolved in fused cryolite is:

The correct option is B to make the fused mixture very conducting
The role of fluorspar is to reduce the melting point of mixture and improve the electrical conductivity of the melt as compared to molten $A l_{2} O_{3}$ . Hence, option B is the correct answer.