Question

The rolling object rolls without slipping down an inclined plane (angle of inclination $\theta$), then the minimum acceleration it can have is :

• A. $gsin\theta$
• B. $\frac{2gsin\theta }{3}$
• C. $\frac{gsin\theta }{2}$
• D. zero

Answer 1

Answer: (C)

$\frac{gsin\theta }{2}$

$a=\frac{gsin\theta }{1+\frac{I}{M{R}^2}}$
a is minimum, if I is maximum.
$I_{max}=M{R}^2$ [for ring]
$\Rightarrow a_{min}=\frac{gsin\theta }{1+\frac{M{R}^2}{M{R}^2}}=\frac{gsin\theta }{2}$