The correct option is C 1.02 v
Given:
Initial root mean square speed, v1=v
Initial temperature of the gas, T1=20∘C=293 K
Change in temperature, ΔT=10 ∘C
So, final temperature of the gas, T2=30∘C=303 K
To find:
Final root mean square speed, v2=?
We know that, root mean square speed is given by,
vrms=√3RTM
Here, R is the gas constant, T is the temperature and M is the molar mass.
So, v1=√3R×293M and
v2=√3R×303M
[ gas is same, so molar mass is same ]
Now, v2v1=√303293
⇒v2≈1.02v1≈1.02 v