The root mean square speed of the molecules of a diatomic gas is v. When the temperature is doubled, the molecules dissociate into two atoms. The new root mean square speed of the atom is :

\sqrt{2 v}

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v

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2 v

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4 v

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Solution

The correct option is C $2 v$
$V_{r m s}$ = $\sqrt{\frac{3 R T}{M}}$ .
According to problem T will become 2T and M will become M/2 so the value of $V_{r m s}$ will increase by $\sqrt{4}$ =2 times
i.e, new root mean square velocity will be $2 v$

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The root mean square speed of the molecules of a diatomic gas is v. When the temperature is doubled, the molecules dissociate into two atoms. The new root mean square speed of the atom is :

The correct option is C 2vVrms = √ 3RTM.According to problem T will become 2T and M will become M/2 so the value of Vrms will increase by √4 =2 timesi.e, new root mean square velocity will be 2v

The correct option is C $2 v$
$V_{r m s}$ = $\sqrt{\frac{3 R T}{M}}$ .
According to problem T will become 2T and M will become M/2 so the value of $V_{r m s}$ will increase by $\sqrt{4}$ =2 times
i.e, new root mean square velocity will be $2 v$