The root mean square value of the alternating current is equal to

Twice the peak value

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Half the peak value

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\frac{1}{\sqrt{2}}

times the peak value

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Equal to the peak value

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Solution

The correct option is C $\frac{1}{\sqrt{2}}$ times the peak value

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Similar questions

The root mean square value of alternating current (sine function) is equal to

\sqrt{2}

50 H z

10

I = 50 \sqrt{2} s i n (400 π t)

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