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Standard XII

Chemistry

Maxwell's Distribution of Speeds

The root mean...

Question

The root mean square velocity of helium molecules at NTP will be :

0.5 x 10

^{5}

m/s

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1.3 x 10

^{3}

m/s

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1.5 x 10

^{6}

m/s

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1.5 x 10

^{7}

m/s

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Solution

The correct option is B 1.3 x 10 $^{3}$ m/s
NTP condition : $T = 298$ K $M = 0.004$ kg/mol

Root mean square velocity $V_{r m s} = \sqrt{\frac{3 R T}{M}}$

$∴$ $V_{r m s} = \sqrt{\frac{3 (8.314) (298)}{0.004}} = 1.36 \times 10^{3}$ m/s

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The root mean square velocity of helium molecules at NTP will be :

The correct option is B 1.3 x 103 m/sNTP condition : T=298 K M=0.004 kg/mol Root mean square velocity Vrms=√3RTM∴ Vrms=√3(8.314)(298)0.004=1.36×103 m/s

The correct option is B 1.3 x 10 $^{3}$ m/s
NTP condition : $T = 298$ K $M = 0.004$ kg/mol

Root mean square velocity $V_{r m s} = \sqrt{\frac{3 R T}{M}}$

$∴$ $V_{r m s} = \sqrt{\frac{3 (8.314) (298)}{0.004}} = 1.36 \times 10^{3}$ m/s