The root mean square velocity of one mole of a mono atomic gas having molar mass M is $U_{r m s}$ . The relation between average kinetic energy (E) if the gas and $U_{r m s}$ is:

U_{r m s} = \sqrt{\frac{3 E}{2 M}}

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U_{r m s} = \sqrt{\frac{2 E}{3 M}}

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U_{r m s} = \sqrt{\frac{2 E}{M}}

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U_{r m s} = \sqrt{\frac{E}{3 M}}

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Solution

The correct option is C $U_{r m s} = \sqrt{\frac{2 E}{M}}$
$U_{r m s}$ = $\sqrt{\frac{3 R T}{M}}$

$K . E = \frac{3}{2} R T$

So, $U_{r m s}$ = $\sqrt{\frac{2 E}{M}}$

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The root mean square velocity of one mole of a mono atomic gas having molar mass M is Urms. The relation between average kinetic energy (E) if the gas and Urms is:

The correct option is C Urms=√2EMUrms = √3RTMK.E=32RTSo, Urms = √2EM

The root mean square velocity of one mole of a mono atomic gas having molar mass M is $U_{r m s}$ . The relation between average kinetic energy (E) if the gas and $U_{r m s}$ is:

The correct option is C $U_{r m s} = \sqrt{\frac{2 E}{M}}$
$U_{r m s}$ = $\sqrt{\frac{3 R T}{M}}$

$K . E = \frac{3}{2} R T$

So, $U_{r m s}$ = $\sqrt{\frac{2 E}{M}}$