The root(s) of the equation (2x−3)=√2x2−2x+21 are?
6
On squaring both sides of the equation, we get
4x2 -12x + 9 = 2x2 - 2x + 21
that gives, 2x2 - 10x - 12 = 0
on solving, we get x = -1 or 6.
But x = -1 does not satisfy the equation. So the valid root of the equation is x = 6.