Question

The roots of $2x^2–6x+8=0$ are

• A. Real and equal
• B. Equal
• C. Imaginary
• D. Real

Answer 1

The correct option is C Imaginary

The value of discrininant of $a{x}^2+bx+c=0$ is $b^2-4ac$

For $2x^2–6x+8=0$,
value of discriminant is given by, $(-6{)}^2–4(2\left)\right(8)=36-64=-28$.

Since discriminant i.e -28 < 0,
roots are imaginary.